Decrease visible records per page

After months of usage, I rarely paginate the list, so it's not necessary
to load 100 at a time. 20 is enough.

By matching 20 records with a 20 pool size, we should keep the repo
queue time to a minimum.
This commit is contained in:
Claudio Ortolina
2024-12-15 11:15:46 +03:00
parent 35435e11c0
commit 6660d195e4
4 changed files with 10 additions and 14 deletions
@@ -10,7 +10,7 @@ defmodule MusicLibraryWeb.CollectionLive.IndexTest do
setup :verify_on_exit!
@default_records_page_size 100
@default_records_page_size 20
@total_records @default_records_page_size + 10
defp fill_collection(_) do
@@ -81,39 +81,35 @@ defmodule MusicLibraryWeb.CollectionLive.IndexTest do
setup [:fill_collection]
test "uses query string params", %{conn: conn, collection: records} do
{:ok, page_2_live, page_2_html} = live(conn, ~p"/collection?page=2&page_size=25")
{:ok, page_2_live, page_2_html} = live(conn, ~p"/collection?page=2&page_size=10")
{page_2_present, page_2_absent} =
Enum.split_with(records, fn record ->
page_2_html =~ record.id
end)
assert length(page_2_present) == 25
assert length(page_2_absent) == @total_records - 25
assert length(page_2_present) == 10
assert length(page_2_absent) == @total_records - 10
page_2_pagination = page_2_live |> with_target("#pagination")
refute has_element?(page_2_pagination, "a", "2")
assert has_element?(page_2_pagination, "a", "1")
assert has_element?(page_2_pagination, "a", "3")
assert has_element?(page_2_pagination, "a", "4")
assert has_element?(page_2_pagination, "a", "5")
{:ok, page_3_live, page_3_html} = live(conn, ~p"/collection?page=3&page_size=25")
{:ok, page_3_live, page_3_html} = live(conn, ~p"/collection?page=3&page_size=10")
{page_3_present, page_3_absent} =
Enum.split_with(records, fn record ->
page_3_html =~ record.id
end)
assert length(page_3_present) == 25
assert length(page_3_absent) == @total_records - 25
assert length(page_3_present) == 10
assert length(page_3_absent) == @total_records - 10
page_3_pagination = page_3_live |> with_target("#pagination")
refute has_element?(page_3_pagination, "a", "3")
assert has_element?(page_3_pagination, "a", "1")
assert has_element?(page_3_pagination, "a", "2")
assert has_element?(page_3_pagination, "a", "4")
assert has_element?(page_3_pagination, "a", "5")
# All records in page 3 were not present in page 2
assert page_3_present -- page_2_absent == []